Optimal. Leaf size=60 \[ \frac{a^2 A \sin (c+d x)}{d}+\frac{b (2 a B+A b) \tanh ^{-1}(\sin (c+d x))}{d}+a x (a B+2 A b)+\frac{b^2 B \tan (c+d x)}{d} \]
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Rubi [A] time = 0.102278, antiderivative size = 60, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.138, Rules used = {4024, 3770, 3767, 8} \[ \frac{a^2 A \sin (c+d x)}{d}+\frac{b (2 a B+A b) \tanh ^{-1}(\sin (c+d x))}{d}+a x (a B+2 A b)+\frac{b^2 B \tan (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 4024
Rule 3770
Rule 3767
Rule 8
Rubi steps
\begin{align*} \int \cos (c+d x) (a+b \sec (c+d x))^2 (A+B \sec (c+d x)) \, dx &=\frac{a^2 A \sin (c+d x)}{d}-\int \left (-a (2 A b+a B)+\left (-A b^2-2 a b B\right ) \sec (c+d x)-b^2 B \sec ^2(c+d x)\right ) \, dx\\ &=a (2 A b+a B) x+\frac{a^2 A \sin (c+d x)}{d}+\left (b^2 B\right ) \int \sec ^2(c+d x) \, dx+(b (A b+2 a B)) \int \sec (c+d x) \, dx\\ &=a (2 A b+a B) x+\frac{b (A b+2 a B) \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a^2 A \sin (c+d x)}{d}-\frac{\left (b^2 B\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{d}\\ &=a (2 A b+a B) x+\frac{b (A b+2 a B) \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a^2 A \sin (c+d x)}{d}+\frac{b^2 B \tan (c+d x)}{d}\\ \end{align*}
Mathematica [A] time = 0.478934, size = 109, normalized size = 1.82 \[ \frac{a^2 A \sin (c+d x)+a (c+d x) (a B+2 A b)-b (2 a B+A b) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+b (2 a B+A b) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )+b^2 B \tan (c+d x)}{d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.045, size = 104, normalized size = 1.7 \begin{align*} 2\,Aabx+B{a}^{2}x+{\frac{A{b}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{{a}^{2}A\sin \left ( dx+c \right ) }{d}}+2\,{\frac{Aabc}{d}}+2\,{\frac{Bab\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{B{b}^{2}\tan \left ( dx+c \right ) }{d}}+{\frac{B{a}^{2}c}{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.989084, size = 139, normalized size = 2.32 \begin{align*} \frac{2 \,{\left (d x + c\right )} B a^{2} + 4 \,{\left (d x + c\right )} A a b + 2 \, B a b{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + A b^{2}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 2 \, A a^{2} \sin \left (d x + c\right ) + 2 \, B b^{2} \tan \left (d x + c\right )}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.503146, size = 294, normalized size = 4.9 \begin{align*} \frac{2 \,{\left (B a^{2} + 2 \, A a b\right )} d x \cos \left (d x + c\right ) +{\left (2 \, B a b + A b^{2}\right )} \cos \left (d x + c\right ) \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (2 \, B a b + A b^{2}\right )} \cos \left (d x + c\right ) \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (A a^{2} \cos \left (d x + c\right ) + B b^{2}\right )} \sin \left (d x + c\right )}{2 \, d \cos \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (A + B \sec{\left (c + d x \right )}\right ) \left (a + b \sec{\left (c + d x \right )}\right )^{2} \cos{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.23978, size = 208, normalized size = 3.47 \begin{align*} \frac{{\left (B a^{2} + 2 \, A a b\right )}{\left (d x + c\right )} +{\left (2 \, B a b + A b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) -{\left (2 \, B a b + A b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) + \frac{2 \,{\left (A a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - B b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - A a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - B b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 1}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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